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±Û¾´ÀÌ :¹ÚÂù¿ì 2000³â 5¿ù 23ÀÏ 17:57:28

In Reply to: StringÀÇ °ü°è¿¬»êÀÚ Àû¿ë¿¡ ´ëÇØ Áú¹® posted by ¿µÁö´Ï on 2000³â 5¿ù 23ÀÏ 16:59:38:


/**
* Compares two strings lexicographically.
* The comparison is based on the Unicode value of each character in
* the strings. The character sequence represented by this
* String object is compared lexicographically to the
* character sequence represented by the argument string. The result is
* a negative integer if this String object
* lexicographically precedes the argument string. The result is a
* positive integer if this String object lexicographically
* follows the argument string. The result is zero if the strings
* are equal; compareTo returns 0 exactly when
* the {@link #equals(Object)} method would return true.
*


* This is the definition of lexicographic ordering. If two strings are
* different, then either they have different characters at some index
* that is a valid index for both strings, or their lengths are different,
* or both. If they have different characters at one or more index
* positions, let k be the smallest such index; then the string
* whose character at position k has the smaller value, as
* determined by using the < operator, lexicographically precedes the
* other string. In this case, compareTo returns the
* difference of the two character values at position k in
* the two string -- that is, the value:
*


* this.charAt(k)-anotherString.charAt(k)
*

* If there is no index position at which they differ, then the shorter
* string lexicographically precedes the longer string. In this case,
* compareTo returns the difference of the lengths of the
* strings -- that is, the value:
*

* this.length()-anotherString.length()
*

*
* @param anotherString the String to be compared.
* @return the value 0 if the argument string is equal to
* this string; a value less than 0 if this string
* is lexicographically less than the string argument; and a
* value greater than 0 if this string is
* lexicographically greater than the string argument.
* @exception java.lang.NullPointerException if anotherString
* is null.
*/
public int compareTo(String anotherString) {}


if (!aa.equals("UA")) {}


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